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| Section | Objectives |
|---|---|
| Object-Oriented Programming | - Encapsulation - Constructors (__init__) - Classes and Objects - Inheritance - Attributes and Methods |
| Control Structures | - Nested Conditionals and Loops - Loops (for, while) - Loop Control (break, continue, pass) - Conditional Statements (if, elif, else) |
| Data Structures | - Sets - Tuples - String Manipulation - Dictionaries - Lists and List Operations |
| Functions | - Scope (local and global) - Recursion - Parameters and Arguments - Return Values - Function Definition and Call |
| File Handling and Exceptions | - Reading and Writing Files - Exception Handling (try, except, finally) - Custom Exceptions |
| Testing and Debugging | - Trace Errors - Unit Testing Concepts - Debugging Techniques |
| Python Fundamentals | - Variables and Data Types - Type Conversion - Input/Output Operations - Operators and Expressions |
Which index position is returned when the string method .find( ' python ' ) is applied to the string ' learning python programming ' ?
Correct Answer: D 🗳️
Explanation: Only visible for Free4Torrent members. You can sign-up / login (it's free).
Write a complete function reverse_string(text) that takes a string and returns it reversed.
For example, reverse_string( " hello " ) should return " olleh " .
def reverse_string(text):
# TODO: Return the reversed string
pass
Correct Answer:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function receives one string parameter named text.
Step 2: Python slicing can be used to reverse a string.
Step 3: The slice [::-1] means start at the end of the string and move backward by one character at a time.
Step 4: Return text[::-1].
Correct code:
def reverse_string(text):
return text[::-1]
Example:
print(reverse_string( " hello " ))
Output:
olleh
Which punctuation mark must appear at the end of an if statement line?
Correct Answer: B 🗳️
Explanation: Only visible for Free4Torrent members. You can sign-up / login (it's free).
Write a complete function password_strength(password) that returns " Strong " if the password is at least 8 characters long and contains both letters and numbers, " Weak " otherwise.
For example, password_strength( " abc123def " ) should return " Strong " .
def password_strength(password):
# TODO: Return " Strong " or " Weak " based on password criteria
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
# TODO: Add your return logic here based on has_letter and has_number
pass
Correct Answer:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: First, check the password length using len(password).
Step 2: If the password has fewer than 8 characters, return " Weak " immediately.
Step 3: Create two Boolean variables: has_letter and has_number.
Step 4: Loop through each character in the password.
Step 5: Use .isalpha() to check for letters and .isdigit() to check for numbers.
Step 6: If the password contains both at least one letter and at least one number, return " Strong " .
Step 7: Otherwise, return " Weak " .
Correct code:
def password_strength(password):
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
if has_letter and has_number:
return " Strong "
else:
return " Weak "
Example:
print(password_strength( " abc123def " ))
print(password_strength( " abcdefgh " ))
print(password_strength( " 12345678 " ))
Output:
Strong
Weak
Weak
Which components are required in every Python while loop?
Correct Answer: D 🗳️
Explanation: Only visible for Free4Torrent members. You can sign-up / login (it's free).
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